10c^2-29cb+10b^2=0

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Solution for 10c^2-29cb+10b^2=0 equation:


Simplifying
10c2 + -29cb + 10b2 = 0

Reorder the terms:
-29bc + 10b2 + 10c2 = 0

Solving
-29bc + 10b2 + 10c2 = 0

Solving for variable 'b'.

Factor a trinomial.
(2b + -5c)(5b + -2c) = 0

Subproblem 1

Set the factor '(2b + -5c)' equal to zero and attempt to solve: Simplifying 2b + -5c = 0 Solving 2b + -5c = 0 Move all terms containing b to the left, all other terms to the right. Add '5c' to each side of the equation. 2b + -5c + 5c = 0 + 5c Combine like terms: -5c + 5c = 0 2b + 0 = 0 + 5c 2b = 0 + 5c Remove the zero: 2b = 5c Divide each side by '2'. b = 2.5c Simplifying b = 2.5c

Subproblem 2

Set the factor '(5b + -2c)' equal to zero and attempt to solve: Simplifying 5b + -2c = 0 Solving 5b + -2c = 0 Move all terms containing b to the left, all other terms to the right. Add '2c' to each side of the equation. 5b + -2c + 2c = 0 + 2c Combine like terms: -2c + 2c = 0 5b + 0 = 0 + 2c 5b = 0 + 2c Remove the zero: 5b = 2c Divide each side by '5'. b = 0.4c Simplifying b = 0.4c

Solution

b = {2.5c, 0.4c}

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